FIRST LAW OF THERMODYNAMICS 115dharm
M-therm/th4-1.pm5From Eqn. (4.31),pv 11 γ = pv 22 γ or p
pv
v2
11
2=FHG IKJ
γ
...(4.36)
From Eqn. (4.34),Tv 11 γγ−−^1 =T v 22 1 orT
Tv
v2
11
21
=F
HGI
KJ−γ
...(4.37)
From Eqn. (4.35),TpTp111221
() ( )γ
γγ
γ−−= orT
Tp
p2
12
11
=FHG IKJ−γ
γ
...(4.38)From eqn. (4.30), the work done in an adiabatic process per kg of gas is given by W
= (u 1 – u 2 ). The gain in internal energy of a perfect gas is given by equation :
u 2 – u 1 = cv (T 2 – T 1 ) (for 1 kg)
∴ W = cv (T 1 – T 2 )
Also, we know that
cv = γ−R 1
Hence substituting, we getW =RT T() 12
1−
−γ
Using equation, pv = RTW =
pv 11 pv2 2
1−
−γ
This is the same expression obtained before as eqn. (4.32).- Polytropic Reversible Process (pvn = constant) :
It is found that many processes in practice approximate to a reversible law of form pvn
= constant, where n is a constant. Both vapours and perfect gases obey this type of law closely in
many non-flow processes. Such processes are internally reversible.
We know that for any reversible process,
W = zpdv
For a process in pvn = constant, we have
p =
C
vn , where C is a constant∴ WCdv
vC v
nC vv
v n nv nnn
==
−+= −
−+F
HGI
z KJ−+ −+ −+
12 1 2 1 1 1
11i.e., WCvv
npv v p v v
nnn nn nn
= −−F
HGI
KJ= −−−+ −+ −+ −+
1
1
2
1
11 1
1
22 2
1
11(since the constant C, can be written as pv
n
11 or as p 2 v 2 n)