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348 ENGINEERING THERMODYNAMICS

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Fig. 7.2. Determination of compressibility from p-T data.

K = –^1
v

v
pT



F
HG

I
KJ

...(7.36)

K can be regarded as a constant for many purposes for solids and liquids. In tables of
properties it is often quoted as an average a value over a small range of pressure at atmospheric
temperature, i.e.,
K = – vv
vp p

21
12 1


()−
When β and K are known, we have


F
HG

I
KJ



F
HG

I
KJ



F
HG

I
KJ

p
T

T
v

v
v p pT

= – 1

Since


F
HG

I
KJ

v
T p
= βv and ∂

F
HG

I
KJ

v
pT
= – Kv,



F
HG

I
KJ

p
T v
= β
K

...(7.37)
When the equation of state is known, the co-efficient of cubical expansion and compressibility
can be found by differentiation. For a perfect gas, for example, we have


F
HG

I
KJ

v
T p =

R
p

v
p

RT
T p

and


F
HG

I
KJ
= 2

Hence β =

1
v

v
T p



F
HG

I
KJ =

R
pv
=^1
T
,

and K = –^1
v

v
pT



F
HG

I
KJ
=

RT
pv^2
=
1
p

7.6.3. Specific heats

Following are the three differential co-efficients which can be relatively easily determined
experimentally.
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