GAS POWER CYCLES 699
dharm
\M-therm\Th13-6.pm5
∴ T 2 ′ =
435 4 293
08
.
.
−
+ 293 = 471 K
Now mf × C = (ma + mf) × cp × (T 3 – T 2 ′)
[ma = mass of air, mf = mass of fuel]
∴ T 3 =
mC
cm m
f
p a f
×
()+
+ T 2 ′ =
1 41800
1.024 (90 1)
×
+ + 471 = 919.5 K
Also, T
T
p
p
4
3
4
3
1
=
F
HG
I
KJ
−γ
γ
or T 4 = T 3 ×
p
p
4
3
1
F
HG
I
KJ
−γ
γ
= 919.5 ×
1.
3.
01
9
14 1
F^14
HG
I
KJ
. −
.
= 625 K
Again, ηturbine =
TT
TT
34
34
−′
−
∴ 0.85 =
919 5
919 5 625
. 4
.
−′
−
T
∴ T 4 ′ = 919.5 – 0.85(919.5 – 625) = 669 K
ηthermal =
()()
()
TT T T
TT
34 2 1
32
−′− ′−
−′
=
−−−
−
(919.5 669) (471 293)=
(919.5 471)
72.5
448.5 = 0.1616 or 16.16%. (Ans.)
Heat Exchanger Cycle. Refer Figs. 13.66 (a) and (b)
T 2 ′ = 471 K (as for simple cycle)
T 3 = 919.5 K (as for simple cycle)
Work
2 ¢
C.C.
CT
Fuel
3
4 ¢
Exhaust
Heat
exchanger
1
Air in
(a)
5