TITLE.PM5

(Ann) #1

GAS POWER CYCLES 703


dharm
\M-therm\Th13-6.pm5


∴ T 7 = 898 –

898 650
085

F −
HG

I


. KJ = 606 K


Also, T
T

p
p

6
7

6
7

1
=
F
HG

I
KJ

−γ
γ

or p
p


T
T

6
7

6
7

1

1 333
898 0 333
606

= 482
F
HG

I
KJ

=F
HG

I
KJ
=

γ
γ

.

..


Then,

p
p

8
9

9
482
=

. = 1.86


Again, T
T

p
p

8
9

8
9

(^1) 1333 1
=F^133316
HG
I
KJ


γ− −
γ
()
.
1.86. 1.
∴ T 9 = T^8
16
898





    1. 16
      = = 774 K




Also, ηturbine (L.P.) =

TT
TT

89
89

−′
− ; 0.85 =

898
898 774

−′ 9

T

∴ T 9 ′ = 898 – 0.85 (898 – 774) = 792.6 K
∴ Net work output = cpg(T 8 – T 9 ′) × 0.95
= 1.15 (898 – 792.6) × 0.95 = 115.15 kJ/kg
Thermal ratio or effectiveness of heat exchanger,

ε=

−′
′− ′
= −

TT
TT

54 T
94

5 428
792.6 428

i.e., 0.8 =
T 5 428
792 6 428



. −
∴ T 5 = 0.8 (792.6 – 428) + 428 = 719.7 K
Now, Heat supplied = cpg(T 6 – T 5 ) + cpg(T 8 – T 7 ′)
= 1.15 (898 – 719.7) + 1.15 (898 – 650) = 490.2 kJ/kg


∴ ηthermal =
Net work output
Heat supplied
=
115 15
490 2

.
.
= 0.235 or 23.5%. (Ans.)
(ii)Work ratio :
Gross work of the plant = Wturbine (H.P.) + Wturbine (L.P.)
= 285.5 +
115 15
095

.
.
= 406.7 kJ/kg

∴ Work ratio ==
Net work output
Gross work output

115 15
406 7

.
.
= 0.283. (Ans.)
(iii)Mass flow rate, m& :
Let the mass flow be m&, then
m& × 115.15 = 4500
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