GAS POWER CYCLES 703
dharm
\M-therm\Th13-6.pm5
∴ T 7 = 898 –
898 650
085
F −
HG
I
. KJ = 606 K
Also, T
T
p
p
6
7
6
7
1
=
F
HG
I
KJ
−γ
γ
or p
p
T
T
6
7
6
7
1
1 333
898 0 333
606
= 482
F
HG
I
KJ
=F
HG
I
KJ
=
−
γ
γ
.
..
Then,
p
p
8
9
9
482
=
. = 1.86
Again, T
T
p
p
8
9
8
9
(^1) 1333 1
=F^133316
HG
I
KJ
γ− −
γ
()
.
1.86. 1.
∴ T 9 = T^8
16
898
- 16
= = 774 K
- 16
Also, ηturbine (L.P.) =
TT
TT
89
89
−′
− ; 0.85 =
898
898 774
−′ 9
−
T
∴ T 9 ′ = 898 – 0.85 (898 – 774) = 792.6 K
∴ Net work output = cpg(T 8 – T 9 ′) × 0.95
= 1.15 (898 – 792.6) × 0.95 = 115.15 kJ/kg
Thermal ratio or effectiveness of heat exchanger,
ε=
−′
′− ′
= −
−
TT
TT
54 T
94
5 428
792.6 428
i.e., 0.8 =
T 5 428
792 6 428
−
. −
∴ T 5 = 0.8 (792.6 – 428) + 428 = 719.7 K
Now, Heat supplied = cpg(T 6 – T 5 ) + cpg(T 8 – T 7 ′)
= 1.15 (898 – 719.7) + 1.15 (898 – 650) = 490.2 kJ/kg
∴ ηthermal =
Net work output
Heat supplied
=
115 15
490 2
.
.
= 0.235 or 23.5%. (Ans.)
(ii)Work ratio :
Gross work of the plant = Wturbine (H.P.) + Wturbine (L.P.)
= 285.5 +
115 15
095
.
.
= 406.7 kJ/kg
∴ Work ratio ==
Net work output
Gross work output
115 15
406 7
.
.
= 0.283. (Ans.)
(iii)Mass flow rate, m& :
Let the mass flow be m&, then
m& × 115.15 = 4500