896 ENGINEERING THERMODYNAMICS
dharm
\M-therm\Th16-2.pm5=
[(.). ][..(.)]
(. ).141 15 221415 141
14 1 1529 59
12 9622
22−× + × × − −
+×= × = 1.32∴ T 2 = 296 × 1.32 = 390.72 K or 117.72°C. Ans.M 22 =
()
()γ
γγ−+
−−12
211
2
12M
M
...[Eqn. (16.49)]= (. ).
..(.)14 1 15 2
21415 14129
592
2−× +
×× − −= = 0.49∴ M 2 = 0.7. Ans.
(ii) Strength of shock :Strength of shock = p
p2
1- 1 = 2.458 – 1 = 1.458. Ans.
 
Highlights
- A compressible flow is that flow in which the density of the fluid changes during flow.
 - The characteristic equation of state is given by :
p
ρ = RT
where p = absolute pressure, N/m^2 ,
ρ = density of gas, kg/m^3 ,
R = characteristic gas constant, J/kg K, and
R = absolute temperature (= t°C + 273). - The pressure and density of a gas are related as :
For isothermal process : p
ρ
= constant 
For adiabatic process : p
ργ= constant.- The continuity equation for compressible flow is given as :
ρAV = constant
dρ
ρ + 
dA
AdV
V
+ = 0 ... in differential form.- For compressible fluids Bernoulli’s equation is given as :
 
(^) ρpg loge p + V
g
2
2
- z = constant ... for isothermal process
γ
γρ−
F
HG
I
KJ 
12
p^2
g
V
g
- z = constant ... for adiabatic process.
 
- Sonic velocity is given by :
 
C = dp
dK
ρρ
= ... in terms of bulk modulus