Mathematical Methods for Physics and Engineering : A Comprehensive Guide

(Darren Dugan) #1

30.3 PERMUTATIONS AND COMBINATIONS


We note that (30.27) may be written in a more general form ifSis not simply

divided intoAandA ̄but, rather, intoanyset of mutually exclusive eventsAithat


exhaustS. Using the total probability law (30.24), we may then write


Pr(B)=


i

Pr(Ai)Pr(B|Ai),

so that Bayes’ theorem takes the form


Pr(A|B)=

Pr(A)Pr(B|A)

iPr(Ai)Pr(B|Ai)

, (30.28)

where the eventAneed not coincide with any of theAi.


As a final point, we comment that sometimes we are concerned only with the

relativeprobabilities of two eventsAandC(say), given the occurrence of some


other eventB. From (30.26) we then obtain a different form of Bayes’ theorem,


Pr(A|B)
Pr(C|B)

=

Pr(A)Pr(B|A)
Pr(C)Pr(B|C)

, (30.29)

which does not contain Pr(B) at all.


30.3 Permutations and combinations

In equation (30.5) we defined the probability of an eventAin a sample spaceSas


Pr(A)=

nA
nS

,

wherenAis the number of outcomes belonging to eventAandnSis the total


number of possible outcomes. It is therefore necessary to be able to count the


number of possible outcomes in various common situations.


30.3.1 Permutations

Let us first consider a set ofnobjects that are all different. We may ask in


how many ways thesenobjects may be arranged, i.e. how manypermutationsof


these objects exist. This is straightforward to deduce, as follows: the object in the


first position may be chosen inndifferent ways, that in the second position in


n−1 ways, and so on until the final object is positioned. The number of possible


arrangements is therefore


n(n−1)(n−2)···(1) =n! (30.30)

Generalising (30.30) slightly, let us suppose we choose onlyk(<n) objects

fromn. The number of possible permutations of thesekobjects selected fromn


is given by


n(n−1)(n−2)···(n−k+1)
︸ ︷︷ ︸
kfactors

=

n!
(n−k)!

≡nPk. (30.31)
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