8.16 DIAGONALISATION OF MATRICES
orthonormal and the transformation matrixSis unitary then
〈e′i|e′j〉=〈∑kSkiek∣
∣
∣∑rSrjer〉=∑kSki∗∑rSrj〈ek|er〉=∑kSki∗∑rSrjδkr=∑kSki∗Skj=(S†S)ij=δij,showing that the new basis is also orthonormal.
Furthermore, in addition to the properties of general similarity transformations,for unitary transformations the following hold.
(i) IfAis Hermitian (anti-Hermitian) thenA′is Hermitian (anti-Hermitian),
i.e. ifA†=±Athen(A′)†=(S†AS)†=S†A†S=±S†AS=±A′. (8.99)(ii) IfAis unitary (so thatA†=A−^1 )thenA′is unitary, since(A′)†A′=(S†AS)†(S†AS)=S†A†SS†AS=S†A†AS=S†IS=I. (8.100)8.16 Diagonalisation of matricesSuppose that a linear operatorAis represented in some basisei,i=1, 2 ,...,N,
by the matrixA. Consider a new basisxjgiven by
xj=∑Ni=1Sijei,where thexjare chosen to be the eigenvectors of the linear operatorA,i.e.
Axj=λjxj. (8.101)In the new basis,A is represented by the matrixA′=S−^1 AS, which has a
particularly simple form, as we shall see shortly. The elementSijofSis theith
component, in the old (unprimed) basis, of thejth eigenvectorxjofA,i.e.the
columns ofSare the eigenvectors of the matrixA:
S=↑↑ ↑
x^1 x^2 ··· xN
↓↓ ↓,