INTEGRAL TRANSFORMS
(i) Differentiation:F[
f′(t)]
=iω ̃f(ω). (13.28)This may be extended to higher derivatives, so thatF[
f′′(t)]
=iωF[
f′(t)]
=−ω^2 ̃f(ω),andsoon.
(ii) Integration:F[∫t
f(s)ds]
=1
iω̃f(ω)+2πcδ(ω), (13.29)where the term 2πcδ(ω) represents the Fourier transform of the constant
of integration associated with the indefinite integral.
(iii) Scaling:F[f(at)]=1
ãf(ωa). (13.30)
(iv) Translation:F[f(t+a)]=eiaω ̃f(ω). (13.31)(v) Exponential multiplication:F[
eαtf(t)]
= ̃f(ω+iα), (13.32)whereαmay be real, imaginary or complex.Prove relation (13.28).Calculating the Fourier transform off′(t) directly, we obtain
F[
f′(t)]
=
1
√
2 π∫∞
−∞f′(t)e−iωtdt=
1
√
2 π[
e−iωtf(t)]∞
−∞+
1
√
2 π∫∞
−∞iω e−iωtf(t)dt=iω ̃f(ω),iff(t)→0att=±∞,asitmustsince
∫∞
−∞|f(t)|dtis finite.To illustrate a use and also a proof of (13.32), let us consider an amplitude-modulated radio wave. Suppose a message to be broadcast is represented byf(t).
The message can be added electronically to a constant signalaof magnitude
such thata+f(t) is never negative, and then the sum can be used to modulate
the amplitude of a carrier signal of frequencyωc. Using a complex exponential
notation, the transmitted amplitude is now
g(t)=A[a+f(t)]eiωct. (13.33)