13.2 LAPLACE TRANSFORMS
f(t) f ̄(s) s 0
cc/s 0
ctn cn!/sn+1 0
sinbt b/(s^2 +b^2 )0
cosbt s/(s^2 +b^2 )0
eat 1 /(s−a) a
tneat n!/(s−a)n+1 a
sinhat a/(s^2 −a^2 ) |a|
coshat s/(s^2 −a^2 ) |a|
eatsinbt b/[(s−a)^2 +b^2 ] a
eatcosbt (s−a)/[(s−a)^2 +b^2 ] a
t^1 /^212 (π/s^3 )^1 /^20
t−^1 /^2 (π/s)^1 /^20
δ(t−t 0 ) e−st^00H(t−t 0 )={
1fort≥t 0
0fort<t 0e−st^0 /s 0Table 13.1 Standard Laplace transforms. The transforms are valid fors>s 0.Comparing this with the standard Laplace transforms in table 13.1, we find that the inverse
transform of 3/sis 3 fors>0 and the inverse transform of 2/(s+1) is 2e−tfors>−1,
and so
f(t)=3− 2 e−t, ifs> 0 .13.2.1 Laplace transforms of derivatives and integralsOne of the main uses of Laplace transforms is in solving differential equations.
Differential equations are the subject of the next six chapters and we will return
to the application of Laplace transforms to their solution in chapter 15. In
the meantime we will derive the required results, i.e. the Laplace transforms of
derivatives.
The Laplace transform of the first derivative off(t) is given byL[
df
dt]
=∫∞0df
dte−stdt=[
f(t)e−st]∞
0 +s∫∞0f(t)e−stdt=−f(0) +sf ̄(s), fors> 0. (13.57)The evaluation relies on integration by parts and higher-order derivatives may
be found in a similar manner.