FIRST-ORDER ORDINARY DIFFERENTIAL EQUATIONS
Solve
dy
dx+
y
x=2x^3 y^4.If we letv=y^1 −^4 =y−^3 then
dy
dx=−
y^4
3dv
dx.
Substituting this into the ODE and rearranging, we obtain
dv
dx−
3 v
x=− 6 x^3 ,which is linear and may be solved by multiplying through by the integrating factor (see
subsection 14.2.4)
exp{
− 3
∫
dx
x}
=exp(−3lnx)=1
x^3.
This yields the solution
v
x^3=− 6 x+c.Remembering thatv=y−^3 ,weobtainy−^3 =− 6 x^4 +cx^3 .
Solution method.Rearrange the equation into the form (14.21) and make the sub-
stitutionv=y^1 −n. This leads to a linear equation inv, which can be solved by the
method of subsection 14.2.4. Then replacevbyy^1 −nto obtain the solution.
14.2.8 Miscellaneous equationsThere are two further types of first-degree first-order equation that occur fairly
regularly but do not fall into any of the above categories. They may be reduced
to one of the above equations, however, by a suitable change of variable.
Firstly, we considerdy
dx=F(ax+by+c), (14.22)wherea,bandcare constants, i.e.xandyonlyappear on the RHS in the particular
combinationax+by+cand not in any other combination or by themselves. This
equation can be solved by making the substitutionv=ax+by+c,inwhichcase
dv
dx=a+bdy
dx=a+bF(v), (14.23)which is separable and may be integrated directly.