CABLES, WIRES AND CABLE INSTALLATION PRACTICES 239Vrun=√
365. 82 ( 0. 2960 × 0. 85 + 0. 0268 × 0. 5268 ) 100
415
= 7 .299%.
From (9.3) for ‘starting’ conditions,cos Ø= 0 .45 and sin Ø= 0. 8930Vstart=√
3460. 74 ( 0. 2960 × 0. 45 + 0. 0268 × 0. 8930 ) 100
415
= 30 .216%.
Table 9.33 shows the volt-drop results for all the available cables.g) Check if the earth loop impedance of the motor circuit is greater than that allowed by the fuses.
The motor circuit is shown in Figure 9.9.
WhereVph=415
Zloopc
Zsec= 0. 00308 +j 0 .0308 ohms/phaseTable 9.33. Volt-drop in the motor feeder cable for the
worked example
Nominal
conductor
area (mm^2 )Running
volt-drop
(%)Starting
volt-drop
(%)Accept
or reject16 7.299 30.216 Reject
25 4.733 20.492 Reject
35 3.498 15.820 Reject
50 2.672 12.792 Accept
70 1.9306 9.800 AcceptFigure 9.9 Circuit diagram for the earth loop impedance.