FAULT CALCULATIONS AND STABILITY STUDIES 281
The contribution from the lower voltage motors is found as follows.
The average ratio of starting current to rated current (Is/In) for the lower voltage motors may be
assumedtobe,
Is
In
= 6 .5 pu for lower voltage motors
Their sub-transient impedanceZlm′′ is
Z′′lm=
1. 0
6. 5
= 0 .153 pu(atSlm)
Typical lower voltage motors have a starting power factor of between 0.25 and 0.35 lagging,
hence assume 0.35.
The sub-transient impedanceZlm′′ of the motors becomes,
Z′′lm= 0. 054 +j 0 .143 pu
The equivalent impedanceZtdof the distribution transformers can be found by the method in
sub-section 11.5.2.5 or taken as,
Ztd= 0. 0 +j 0 .055 pu(atStd)
Again assume that the air-gap emfElm′′ is 1.0 pu.
The contributionIlm′′ from the lower voltage motors is,
Ilm′′ =
Elm′′
(
Z′′lm
Slm
+
Ztd
2 Ktd(Slm+Sls)
)
Sbase
=
1. 0 Slm
(
0. 054 +j 0. 143 +
j 0. 06
Ktd2
)
Sbase
(11.3)
Where
Ktd2= 2 Ktd
(
1. 0 +
Sls
Slm
)
The total sub-transient symmetrical rms fault currentIfrms′′ is,
Ifrms′′ =Ig′′+Ihm′′ +Ilm′′ ( 11. 4 )
11.6.1 Calculate the sub-transient peak fault current contributions
Many power system networks can be reduced to a simple series-connected circuit containing a resis-
tanceRand an inductanceL, for the purpose of calculating the transient fault current. Furthermore a