rxyqWe havex^2 +y^2 =r^2Dividing byr^2 gives
(x
r) 2
+(y
r) 2
= 1or cos^2 θ+sin^2 θ= 1Thisidentity should definitely become second nature to you – it is absolutely vital. By
dividing through by cos^2 θwe get 1+tan^2 θ=sec^2 θand dividing through by sin^2 θgives
cot^2 θ+ 1 =cosec^2 θ, so there is no need to remember all three identities.
Solution to review question 6.1.6(i) Using cos^2 θ+sin^2 θ=1wehavecos^2 θ= 1 −sin^2 θ= 1 −1
49=48
49
so
cosθ=√
48
49in first quadrant=4√
3
7
Then tanθ=sinθ
cosθ=1 / 7
4√
3 / 7=1
4√
3(ii) sinθ=√
1 −cos^2 θ=√
1 −1
3=√
2
3tanθ=√ 2 3 1 √ 3=√
2(iii) sec^2 θ=1
cos^2 θ= 1 +tan^2 θ= 1 +(
1
√
2) 2
=3
2