Understanding Engineering Mathematics

(やまだぃちぅ) #1
− 2 + 2 j

3 j

− j

1 + j√ 3

−√ 3 − j

− 3 − 3 j

− (^102)
y
x
11.(i) 4 (ii) − 3 j (iii) − 2
(iv) − 10 (v) 10j (vi)

2 +

2 j
(vii)
3

2

3

2
j (viii) −

2 −

2 j (ix)

3
2



  • 3
    2
    j
    (x) −
    3
    2

    3

    3
    2
    j (xi)

    3
    2


  • 1
    2
    j (xii) −
    3

    3
    2

    3
    2
    j





  1. z 1 = 5 ( 1 +j



3 )/ 2 z 2 = 3 ( 1 +j)/


2

(i) 15 (ii) 5/ 3 (iii) 25

(iv) 7π/ 12 (v) π/ 12 (vi) 2π/ 3


  1. (i) 6^


(
2 π
9

)
(ii)

3
2

(
π
9

)
(iii) 6^

(
5 π
9

)

(iv) 2^

(

11 π
18

)
(v)

2
3

(
2 π
9

)
(vi)

9
2

(
11 π
18

)

15.(i) 16 (ii) − 64 (iii) − 64


16.(i)



2 e−jπ/^4 (ii) 2ejπ/^2 (iii) 2ejπ/^6 (iv) 3e−jπ/^2


  1. (i)


1
2

+


3
2

j (ii)


3
2


1
2

j (iii)

e−^1 /^3
2



3 e−^1 /^3
2

j

(iv)


3
2


1
2

j (v)

3
5


2


1
5


2

j (vi)

2


3 + 1
10


2 −


3
10

j
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