Table 17.1
f(t) f(s) ̃ =F(s)=L[f(t)]
1
1
s
(s > 0 )
t^1
s^2
(s > 0 )
tn(na positive integer)
n!
sn+^1 (s >^0 )
eat
1
s−a
(s > a)
tneat
n!
(s−a)n+^1
(s > a)
sinωt ω
s^2 +ω^2
(s > 0 )
cosωt s
s^2 +ω^2
(s > 0 )
tsinωt^2 ωs
(s^2 +ω^2 )^2
(s > 0 )
tcosωt s
(^2) −ω 2
(s^2 +ω^2 )^2
(s > 0 )
eatsinωt
ω
(s−a)^2 +ω^2
(s > a)
eatcosωt
s−a
(s−a)^2 +ω^2
(s > a)
discontinuity must be finite. We can integrate such a function by integrating the continuous
sections separately.
A well known example of a piecewise continuous function is theunit (or Heaviside)
step function, shown in Figure 17.1, defined by
H(t)= 0 t< 0
= 1 t> 0
0 t
1
H(t)
Figure 17.1The step function.
This function is discontinuous att=0 and yet has a continuous Laplace transform, namely
1 /s. Integration effectively smoothes things out.