36 CHAPTER 2. ELECTRONIC LEVELS IN SEMICONDUCTORS
EXAMPLE 2.1Calculate the density of states of electrons in a 3D system and a 2D system at an energy
of 1.0 eV. Assume that the background potential is zero.
The density of states in a 3D system (including the spin of the electron) is given by (Eis the energy in
Joules)
N(E)=√
2(m 0 )^3 /^2 E^1 /^2
π^2 ^3
=√
2(0. 91 × 10 −^30 kg)(E^1 /^2 )
π^2 (1. 05 × 10 −^34 J·s)^3
=1. 07 × 1056 E^1 /^2 J−^1 m−^3ExpressingEin eV and the density of states in the commonly used units of eV−^1 cm−^3 ,weget
N(E)=1. 07 × 1056 ×(1. 6 × 10 −^19 )^3 /^2 (1. 0 × 10 −^6 )E^1 /^2
=6. 8 × 1021 E^1 /^2 eV−^1 cm−^3AtE=1. 0 eV we get
N(E)=6. 8 × 1021 eV−^1 cm−^3
For a 2D system the density of states is independent of energy and is
N(E)=m^0
π^2=4. 21 × 1014 eV−^1 cm−^22.3.1 Particle in a periodic potential: Bloch theorem
Band theory, which describes the properties of electrons in a periodic potential arising from
the periodic arrangement of atoms in a crystal, is the basis for semiconductor technology.
The Schrodinger equation in the crystal ̈
[
−^2
2 m 0
∇^2 +U(r)]
ψ(r)=Eψ(r) (2.3.9)whereU(r)is the background potential seen by the electrons. Due to the crystalline nature of
the material, the potentialU(r)has the same periodicity
U(r)=U(r+R)We have noted earlier that if the background potential isV 0 , the electronic function in a volume
Vis
ψ(r)=eik·r
√
V
and the electron momentum and energy are
p = kE =^2 k^2
2 m 0