Part I Proofs
Bogus proof.
aDb
a^2 Dab
a^2 b^2 Dab b^2
.a b/.aCb/D.a b/b
aCbDb
aD0:
Problem 0.2.
It’s a fact that the Arithmetic Mean is at least as large the Geometric Mean, namely,
aCb
2
p
ab
for all nonnegative real numbersaandb. But there’s something objectionable
about the following proof of this fact. What’s the objection, and how would you fix
it?
Bogus proof.
aCb
2
‹
p
ab; so
aCb
‹
2
p
ab; so
a^2 C2abCb^2
‹
4ab; so
a^2 2abCb^2
‹
0; so
.a b/^2 0 which we know is true.
The last statement is true becausea bis a real number, and the square of a real
number is never negative. This proves the claim.
Problem 0.3.
Albert announces to his class that he plans to surprise them with a quiz sometime
next week.