Chapter 6 Induction140
Problem 6.3.
Prove by induction:
1 C
1
4
C
1
9
CC
1
n^2
< 2
1
n
; (6.7)
for alln > 1.
Problem 6.4. (a)Prove by induction that a 2 n 2 ncourtyard with a 1 1 statue
of Bill ina cornercan be covered with L-shaped tiles. (Do not assume or reprove
the (stronger) result of Theorem 6.1.1 that Bill can be placed anywhere. The point
of this problem is to show a different induction hypothesis that works.)
(b)Use the result of part (a) to prove the original claim that there is a tiling with
Bill in the middle.
Problem 6.5.
We’ve proved in two different ways that
1 C 2 C 3 CCnD
n.nC1/
2
But now we’re going to prove acontradictorytheorem!
False Theorem.For alln 0 ,
2 C 3 C 4 CCnD
n.nC1/
2
Proof. We use induction. LetP.n/be the proposition that 2 C 3 C 4 CCnD
n.nC1/=2.
Base case:P.0/is true, since both sides of the equation are equal to zero. (Recall
that a sum with no terms is zero.)
Inductive step:Now we must show thatP.n/impliesP.nC1/for alln 0. So
suppose thatP.n/is true; that is, 2 C 3 C 4 CCnDn.nC1/=2. Then we can
reason as follows:
2 C 3 C 4 CCnC.nC1/DŒ 2 C 3 C 4 CCnçC.nC1/
D
n.nC1/
2
C.nC1/
D
.nC1/.nC2/
2