Chapter 2 The Well Ordering Principle30
LetCbe the set ofcounterexamplesto (*), namely^3
CWWDfnj:::g
Assume for the purpose of obtaining a contradiction thatCis nonempty.
Then by the WOP, there is a smallest number,m 2 C. Thismmust be
positive because....
But ifS.m/holds andmis positive, thenS.m 6/orS.m 15/must
hold, because....
So supposeS.m 6/holds. Then 3 j.m 6/, because...
But if 3 j.m 6/, then obviously 3 jm, contradicting the fact thatm
is a counterexample.
Next, ifS.m 15/holds, we arrive at a contradiction in the same way.
Since we get a contradiction in both cases, we conclude that...
which proves that (*) holds.
Problem 2.3.
Euler’s Conjecturein 1769 was that there are no positive integer solutions to the
equation
a^4 Cb^4 Cc^4 Dd^4 :
Integer values fora;b;c;dthat do satisfy this equation, were first discovered in
- So Euler guessed wrong, but it took more two hundred years to prove it.
Now let’s consider Lehman’s equation, similar to Euler’s but with some coeffi-
cients:
8a^4 C4b^4 C2c^4 Dd^4 (2.2)
Prove that Lehman’s equation (2.2) really does not have any positive integer
solutions.
Hint:Consider the minimum value ofaamong all possible solutions to (2.2).
Homework Problems
Problem 2.4.
Use the Well Ordering Principle to prove that any integer greater than or equal to 8
can be represented as the sum of integer multiples of 3 and 5.
(^3) The notation “fnj:::g” means “the set of elements,n, such that... .”