Jesús de la Peña Hernández
Fig. 4 will allow us to find the dihedral angle ε formed by two adjacent faces of a do-
decahedron, as well as its diameter. At left we have two pentagons like those in Fig. 3 and, as-
sociated with them, segments l, d, D and A. The value of the latter is:
A = a + r = 0,6881909 l + 0,8506508 l = 1,5388417 lThe figure at right is a hemispherical section of a dodecahedron; in it, D is the diagonal
of the great pentagon at left (see Fig. 3, Point 18.6.3). To draw that section we shall start by
∆YVW whose three sides are given. In it we get ε:AD
2 2sen =ε
; ε = 116,56505 ºThe figure at right is symmetric with respect to XY; points V in it are vertices of the do-
decahedron. After all that we can deduce:- the angle γ in the irregular hexagon with sides A, l:
180 (6 – 2 ) = 2 ε + 4 γ ; 121 , 71748
4720 2 116 , 56505
=
− ×
γ =- the proof that angle VWV is a right one:
Ang. VWV = 90
2180 116 , 56505
121 , 71748
2180
=
−
= −
−
−ε
γA
lB d CDd
d4
AD AVVllAAWXZ YO2
d2ld3
DA l B d C