Jesús de la Peña Hernández
18.9.5 Skeletonlike OCTAHEDRON
Folding angle of profile 3 is 109,47123º, twice as much as angle α in Point
18.2.2.2.
18.10 Perforated PENTAGONAL-DODECAHEDRON
C = 12 ; V = 20 ; A = 30
To optimise paper use, start with an argentic rectangle close in size to an A4, and follow
up this process:
1- To divide both sides of that argentic rectangle in 10 equal parts to get 100 small
argentic rectangles like the one outlined in Fig. 1.
2- Zigzag draw the diagonals of those 100 rectangles and then clear out their small
sides. (Recall Point 10.1.3).
The bases of those pyramids are
shown in Fig. 2 (Figs. 1 and 2 are not to
the same scale); in it we can see 4 cuts in-
dicated by dotted lines. Finally place one
base against the other, turn around and
interlock both domes (Fig. 3).
C
O
E F A
2
B
h h
3
O
B
Fig. 1 is the finished octahedron (inter-
nal folds of corners are not shown for the sake
of simplicity). It has a structure similar to that
of the tetrahedron in Fig. 7, Point 18.7: to con-
struct this octahedron we require 6 paper cor-
ners for the vertices (Fig. 2), and 12 cardboard
profiles for the sides (Fig. 3).
Vertices should be glued for fixing in
areas such as OAF and also where Figs. 2 and
3 meet. The crease of Fig. 3 will lie under OC
in the assembly.
Profiles to Fig. 3 may have any length
(as long as all of them are equal) but they
should keep the right proportion with the cor-
ners.