MATHEMATICS AND ORIGAMI

Mathematics and Origami

AC

CB CB

AB = ; CB^2 =AB×AC

It is pertinent to quote now that rectangle ABCD in Point 6.6.6 is an auric one (S. Turrión). If that would be the case, we should have:

AB^2 = CB (CB – AB )

expression that is equivalent to the following identity which confirms the hypothesis:

  

   

 −  = × − 

   

 − 2

5 1 1 1 2

5 1

2

Interlude