SECTION 2.1 Elementary Number Theory 101
However, given thatu 0 = 0, u 1 = 1, we get0 = A
1 = Acos
2 π
3+Bsin
2 π
3=−
A
2
+
√
3 B
2
ThereforeA= 0 andB=√^2
3
, forcing the solution to beun =2
√
3
sin2 πn
3, n= 0, 1 , 2 ,....Higher-degreecharacteristic polynomials.
We won’t treat this case systematically, except to say that upon
factoring the polynomial into irreducible linear and quadratic fac-
tors, then one can proceed as indicated above (see Exercise 14).
Additional complications result with higher-order repeated factors
which we don’t treat here.Higher-order differences
In Section 2.1.9 we treated only the so-called homogeneous linear
difference equations. An inhomogeneous linear difference equation
has the general form
C(u) =v,whereC(x) is a monic polynomial,v= (vn)n≥ 0 is a given sequence and
whereu= (un)n≥ 0 is the unknown sequence.
We have already encountered such an example above, in the example
on page 312 giving an arithmetic sequence:
un+1−un=d, n= 0, 1 , 2 ,....We won’t treat inhomogeneous linear difference equations in any
detail except for a very special case, namely those having constant