SECTION 5.2 Numerical Series 267
Fact 2: If Fact 1 is true, we still need to show that there is some
numberM such that∑k
n=0an≤M for allk.Fact 3: Even when we have verified Facts 1 and 2, we still might
not (and usually won’t) know the actual limit of the infinite series
∑∞
n=0an.Warning about Fact 1: the requirement that limn→∞an = 0 is a
necessary but not sufficientcondition for convergence. Indeed, in
the above we saw that the series
∑∞
n=11
n
divergesbut that∑∞
n=11
n^2
con-verges.
Exercises
- ApplyFact 1above to determine those series which definitely will
not converge.
(a)∑∞
n=0n
n+ 1(b)∑∞
n=0(−1)n
n(c)∑∞
n=2lnn
n(d)∑∞
n=0n
(lnn)^2(e)∑∞
n=1sinn
n(f)∑∞
n=0(−1)nsinn(g)∑∞
n=2(−1)nn^2
2 n(h)∑∞
n=0n!
2 n(i)∑∞
n=2lnn
ln(n^2 + 1)- Occassionally an infinite series can be computed by using a partial
fraction decomposition. For example, note that
1
n(n+ 1)=
1
n−
1
n+ 1and so∑∞
n=11
n(n+ 1)=
∑
n=1(
1
n−
1
n+ 1)=
(
1 −1
2
)
+( 1
2
−
1
3
)
+( 1
3
−
1
4
)
+···= 1.Such a series is called a “telescoping series” because of all the
internal cancellations. Use the above idea to compute