Advanced High-School Mathematics

(Tina Meador) #1

276 CHAPTER 5 Series and Differential Equations


(c)

∑∞
n=1

n^2

n^7 + 2n

(d)

∑∞
n=0

n^2 + 2n
3 n

(e)

∑∞
n=0

(n+ 1)3n
n!

(f)

∑∞
n=1

2 n
nn

(g)

∑∞
n=1

n!
nn

(h)

∑∞
n=1

(^1

1 +^1 n

)n


  1. As we have already seen, the series


∑∞
n=1

1

n^2

, converges. In fact, it is

known that

∑∞
n=1

1

n^2

=

π^2
6

; a sketch of Euler’s proof is given on page
228 of the Haese-Harris textbook.^11 Using this fact, argue that

∑∞
n=0

1

(2n+ 1)^2

=

π^2
8

.


  1. Prove thesinusoidal p-series test, namely that


∑∞
n=1

sin

(
2 π
np

)


converges ifp > 1 ,
diverges ifp≤ 1.

(Of course, the 2πcan be replaced by any constant. Exercise 2 on
page 256 is, of course, relevant here!)


  1. Recall Euler’sφ-functionφ(see page 63). Determine the behavior
    of the series


∑∞
n=1

1

nφ(n)

.(See Exercise 16d on page 64.)


  1. How about


∑∞
n=1

φ(n)
n^2

?


  1. Let F 0 , F 1 , F 2 , ... be the terms of the Fibonacci sequence (see
    page 93). Show that


∑∞
n=0

Fn
2 n

converges and compute this sum ex-
plicitly. (Hint: you’ll probably need to work through Exercise 7
on page 106 first.)

(^11) Peter Blythe, Peter Joseph, Paul Urban, David Martin, Robert Haese, and Michael Haese,
Mathematics for the international student; Mathematics HL (Options), Haese and
Harris Publications, 2005, Adelaide, ISBN 1 876543 33 7

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