Tensors for Physics

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140 8 Integration of Fields


8.3.6 Integration by Parts.


Letf=f(r)andg=g(r)be two field functions. Due to the product rule∇μ(gf)=
g∇μf+f∇μg, and with the help of the generalized Gauss theorem, the volume
integral



Vg∇μfis equal to

V

g∇μfd^3 r=−


V

f∇μgd^3 r+


∂V

fgnμd^2 s. (8.82)

In many applications, the surface integral



∂Vfgnμd

(^2) sis taken over a surface, where
at least one of the two functionsfandgvanishes. Then, the integration by parts is
equivalent to ∫
V
g∇μfd^3 r=−



V

f∇μgd^3 r. (8.83)

Withf=−∇μgandΔ=∇μ∇μ, the relation (8.83) implies




V

gΔgd^3 r=


V

(∇μg)(∇μg)d^3 r≥ 0. (8.84)

Thus, subject to the condition that the contribution of the surface integral, occurring
in connection with the integration by parts, is zero, the negative Laplace operator
−Δis a positive definite operator. This point is of importance for the kinetic energy
operator in wave mechanics, cf. Sect.7.6.4.


8.4 Further Applications of Volume Integrals.


8.4.1 Continuity Equation, Flow Through a Pipe


The mass density and the local velocity field of a fluid are denoted byρ=ρ(r)
andv=v(r), as in Sect.7.4.3. The vector fieldj(r)=ρvis theflux density.The
continuity equation, cf. (7.49),


∂ρ
∂t

+∇νjν= 0 , (8.85)

expresses thelocal conservationof mass. The integral ofρover a volumeVyields
the massMV=



Vρd

(^3) rcontained withinV. Upon integration of the continuity
equation over a volumeVwhich does not change with time, the first term of the
equation is the time change of the massMV. The second term can be expressed as a
surface integral over∂V, due to the Gauss theorem. Thus (8.85) leads to

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