146 8 Integration of Fields
cf. Sects.2.6.4and5.3.4. Then the energy density is equal to
u=
1
2
EνDν=
1
2
ε 0 ενμEμEν. (8.104)
Clearly, the symmetric part ofενμonly contributes to the energy density.
The energy density for the more general case of a nonlinear relation between the
DandEfields is treated in Sect.8.5.3.
8.5.2 Force and Maxwell Stress in Electrostatics.
The forceFμacting on chargesqj, in vacuum, in the presence of a given electric
fieldEμis
Fμ=
∑
j
qjEμ(rj),
or, in terms of the charge densityρ,by
Fμ=
∫
ρ(r)Eμ(r)d^3 r=
∫
kelstatμ d^3 r. (8.105)
With the help of the Gauss lawρ=∇νDν,cf.(7.56), the electrostatic force density
kμelstatcan be rewritten as
kelstatμ =Eμ∇νDν=∇ν(DνEμ)−Dν∇νEμ. (8.106)
In electrostatics, one has∇×E=0, and consequently∇νEμ=∇μEν. Thus the last
term of (8.106) is equal toDν∇μEν. Provided that the interrelation betweenDandE
is linear, this term can also be written as the total spatial derivative( 1 / 2 )∇μ(EνDν).
Thus in vacuum, and the same applies for any linear medium, the force density is
given by
kelstatμ =∇ν(DνEμ)−
1
2
∇μ(EλDλ)=∇ν(DνEμ)−
1
2
∇μ(EλDλδμν)=∇νTνμelstat.
(8.107)
The electrostatic stress tensor for a linear medium is defined by
Tνμelstat≡DνEμ−
1
2
EλDλδμν. (8.108)
This tensor is symmetric, i.e.Tνμelstat=Tμνelstat, in vacuum and for an isotropic linear
medium, whereDν=εε 0 Eνapplies, with a scalar dielectric coefficientε. In general