10.1 Descending Multipoles 165
∇μ∇νr−^1 =Xμν(r)−
4 π
3
δμνδ(r), (10.7)
whereXμν(r)is given by (10.5).
To verify (10.7), integrate it over a sphere with a finite radiusR, centered atr=0.
More specifically, use the Gauss theorem for
∫
∇μ(∇νr−^1 )d^3 rto obtain
∫
∇μ∇νr−^1 d^3 r=R^2
∫
rˆμ
(
∇νr−^1
)
r=R
d^2 rˆ=−
∫
rˆμrˆνd^2 rˆ=−( 4 π/ 3 )δμν.
Notice that d^3 r=r^2 drd^2 rˆ, that the integral of the symmetric traceless tensorXμν
over the sphere vanishes since
∫
rˆμrˆνd^2 rˆ =0, and that theδ-function has the
property
∫
δ(r)d^3 r=1.
The trace of (10.7) yields
Δr−^1 =− 4 πδ(r). (10.8)
The Poisson equation of electrostatics or the electric potentialφ∼r−^1 in vacuum,
caused by a point chargeqlocated atr=0, viz.ε 0 Δφ=− 4 πqδ(r), is mathemat-
ically equivalent to (10.8). The Poisson equation, in turn, is a consequence of the
Gauss law of electrodynamics, cf. Sect.7.5.
10.1.4 General Properties of Multipole Potentials
In general, the-th multipole potential can be written as
Xμ 1 μ 2 ···μ=( 2 − 1 )!!r−(^2 +^1 )rμ 1 rμ 2 ···rμ, (10.9)
or equivalently
Xμ 1 μ 2 ···μ(r)=r−(+^1 )Yμ 1 μ 2 ···μ(rˆ), (10.10)
with the tensors
Yμ 1 μ 2 ···μ(rˆ)=( 2 − 1 )!!̂rμ 1 ̂rμ 2 ···̂rμ. (10.11)
The irreducible tensorsY...depend on the direction ofronly. With the unit vector
ˆrexpressed in terms of the polar angles, the components of the-th rank Cartesian
tensor are isomorphic to the spherical harmonicsYm.
Clearly, cf. (10.10), the-th rank multipole potential is proportional to
r−(+^1 ).