380 Cosmic microwave background anisotropies
Problem 9.9Show thatηx/η 0 Iz−x^1 /^2 ,where
I≡ 3
(
(^)
(^) m
) 1 / 6 ⎡
⎣
∫y
0
dx
(sinhx)^2 /^3
⎤
⎦
− 1
(9.84)
andy≡sinh−^1 ( (^) /
m)^1 /^2 .In a flat universe (^) = 1 − (^) m,and the numerical
fitting formula
I −m^0.^09 (9.85)
approximates (9.84) to an accuracy better than 1% over the interval 0. 1 <
m< 1.
Verify thatηx/ηris equal to
ηr
ηx
(
zx
zeq
) 1 / 2 [(
1 +
zeq
zr
) 1 / 2
− 1
]
. (9.86)
Combining the relations from Problem 9.9 we obtain
ηr
η 0
=
1
√
zr
[(
1 +
zr
zeq
) 1 / 2
−
(
zr
zeq
) 1 / 2 ]
I. (9.87)
Using this result together with (9.60) forσ, (9.78) becomes
lf 1530
(
1 +
zr
zeq
) 1 / 2
I−^1 , (9.88)
where we recall from (9.61) that
zr
zeq
7. 8 × 10 −^2
(
(^) mh^275
)− 1
(9.89)
for three neutrino species.
The result is that the finite thickness damping coefficientlfdepends only weakly
on the cosmological term and (^) mh^275 .For (^) mh^275 0 .3 and (^) h^275 0 .7, we have
lf 1580 ,whereas for (^) mh^275 1 and (^) h^275 0, we findlf 1600.
The scalelSdescribing the combination of finite thickness and Silk damping
effects can be calculated in a similar way.
Problem 9.10Using the estimate (9.62) for the Silk dissipation scale, show that
lS 0. 7 lf
⎧
⎪⎨
⎪⎩
1 + 0. 56 ξ
1 +ξ
+
0. 8
ξ( 1 +ξ)
(
(^) mh^275
) 1 / 2
[
1 +
(
1 +zeq/zr
)− 1 / 2 ]^2
⎫
⎪⎬
⎪⎭
− 1 / 2
. (9.90)