1.3. Radioactivity and Radioactive Decay 23
Activity
AP
AD
T1/2P>>T1/2D
Time
Figure 1.3.6: Activities of par-
ent and daughter nuclides as a
function of time for a material
that eventually reaches the state
of secular equilibrium. The half
life of parent in such a material
is so large that it can be consid-
ered stable.
Solution:
Since the half life of the parent is much larger than that of the daughter,
therefore we can safely assume that at the state of secular equilibrium the
activity of the daughter will be nearly equal to the initial activity of the
parent, that is.
ADA 0 P.
Substitution of this equality in equation 1.3.32 gives
λdD
λdD−λdP
e−λdPt 1
⇒t
1
λdP
ln
(
λdD
λdD−λdP
)
.
The decay constants of the two materials are
λdP =
ln(2)
T 1 P/ 2
=
ln(2)
2. 14 × 106 × 365
=8. 87 × 10 −^10 day−^1
λdD =
ln(2)
T 1 D/ 2
=
ln(2)
27
=2. 57 × 10 −^2 day−^1
Hence the required time is given by
t
1
8. 87 × 10 −^10
ln
(
2. 57 × 10 −^2
2. 57 × 10 −^2 − 8. 87 × 10 −^10
)
.
=38.9days