- E2 reaction
- E1 reaction
6.17 THE E2 REACTION
- Rate equation
Rate = k [CH 3 CHBrCH 3 ] [C 2 H 5 O–]
A Mechanism for the E2 Reaction
Reaction:
C 2 H 5 O– + CH 3 CHBrCH 3 CH 2 =CHCH 3 + C 2 H 5 OH + Br–
Mechanism:
CH 3 CH 2 O−
CH 3 CH 2 O
δ−
CH 3 CH 2 O
CC
H
Br
HCH 3
HH
β α CC
H
Br
HCH 3
HH
β α δ−
Transition state
++
The basic ethoxide ion begins to remove
a proton from the β-carbon using its
electron pair to form a bond to it. At the
same tim, the electron pair of the β
C−H bond begins to move in to become
the π bond of a double bond, and the
bromide begins to depart with the
electrons that bonded it to the α carbon.
Partial bonds now exist between the
oxygen and the β hydrogen and
between the α carbonand the
bromine. The carbon-carbon bond is
developing double bond character.
CC
H
CH 3
H
H
+ H + Br −
Now the double bond of the alkene is fully formed
and the alkene has a trigonal plannar geometry at
each carbon atom. The other products are a
moleculeofethanolanda bromide ion.
(^)