CH 3 (CH 2 ) 15 CH 2 CH 2 Br (CH^3 )^3 CO CH 3 (CH 2 ) 15 CH CH 2−K+
(CH 3 ) 3 COH
40 oC 85%- Dehydrohalogenation of many alkyl halides yields more than one product:
B −BB(a) H(a)(a)
(b)
CH 3 CH CH CH 2CH 3Br(b)(b)CH 3 CH CCH 3CH 3H Br −CH 3 CH 2 CCH 2CH 3H Br −++++2-Methyl-2-butene2-Methyl-1-butene2-Bromo-2-methylbutane1) When a small base such as ethoxide ion or hydroxide ion is used, the major
product of the reaction will be the more stable alkene.CH 3 CH 2 O− CH 3 CH 2 CCH 3
CH 3Br70 oC
CH 3 CH 2 OH CH^3 CH CCH 3
CH 3CH 3 CH 2 CCH 2CH 3+ +2-Methyl-2-butene
(69%)
(more stable)2-Methyl-1-butene
(31%)
(less stable)
i) The more stable alkene has the more highly substituted double bond.- The transition state for the reaction:
C 2 H 5 O−+C 2 H 5 Oδ−CC C 2 H 5 OHBrCCHBrδ−Η ++CC Br−Transition state for an E2 reaction
The carbon-carbon bond has some
of the characterof a double bond.
1) The transition state for the reaction leading to 2-methyl-2-butene has the