A Mechanism for the Reaction
Acid-Catalyz ed Dehydration of Secondary or Tertiary Alcohols: An E1 Reaction
Step 1
+
Protonated alcohol
fast
2 o or 3o Alcohol Strong acid Conjugate base
The alcohol accepts a proton from the acid in a fast step.
C O H
H
O H H A + A−
R
R'
C
H
C
R
R'
C
H
+
(R' may be H) (typically sulfuric or^
phosphoric acid)
Step 2
slow
The protonated alcohol loses a molecule of water to become a carbocation.
C O H
H
+ OH
R H
R'
C
H (rate determining)
C C +
H R'
R
+
This step is slow and rate determining
Step 3
The carbocation loses a proton to a base. In this step, the base may be another
molecule of the alcohol, water, or the conjugate base of the acid. The proton
transfer results in the formation of the alkene. Note that the overall role of the
acid is catalytic (it is used in the reaction and regenerated).
Alkene
C C
H R'
R
+ +
fast C CR'
R
A − + H A
(^)
- The order of free energy of activation for dehydration of alcohols is 3° > 2° > 1° >
methyl: