H 2 CCHCH 2 H + Br H 2 CCHCH 2 + H Br
H 2 CCHCH 2 + Br Br H 2 CCHCH 2 Br + Br
3) NBS is nearly insoluble in CCl 4 and provides a constant but very low
concentration of bromine in the reaction mixture.
i) NBS reacts very rapidly with the HBr formed in the substitution reaction ⇒
each molecule of HBr is replaced by one molecule of Br 2.
N
O
O
O
O
Br + HBr N H + Br 2
ii) In a nonpolar solvent and with a very low concentration of bromine, very
little bromine adds to the double bond; it reacts by substitution and replaces an
allylic hydrogen atom.
- Why does a low concentration of bromine favor allylic substitution over
addition?
- The mechanism for addition of Br 2 to a double bond:
Br Br Br− Br
Br
C
C
C
C
+++Br C
C
i) In the first step only one atom of the bromine molecule becomes attached to the
alkene in a reversible step.
ii) The other atom (now the bromide ion) becomes attached in the second step.
iii) If the concentration of bromine is low, the equilibrium for the first step will lie
far to the left. Even when the bromonium ion forms, the probability of its