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Inorganic and Applied Chemistry
Example 3- C:
Decomposition of nitrogen dioxid
In an experiment we begin by having a flask of gas filled with NO 2 at room temperature (25 ºC). At this
temperature NO 2 is stabile, but if the gas is heated up to 300 ºC, it decompose to NO and O 2 following the
following reaction scheme:
2 NO 2 (g) 2 NO(g) + O 2 (g)
By measurement of the concentration of the three gases as function of time, the following data is obtained:
Time in
seconds
Concentration of NO 2 Concentration of NO Concentration of O 2
0 0,01 0 0
50 0,0079 0,0021 0,0011
100 0,0065 0,0035 0,0018
150 0,0055 0,0045 0,0023
200 0,0048 0,0052 0,0026
250 0,0043 0,0057 0,0029
300 0,0038 0,0062 0,0031
350 0,0034 0,0066 0,0033
400 0,0031 0,0069 0,0035
By applying equation (3-1) it becomes possible to determine the velocity, by which O 2 is formed. For
instance is O 2 formed in the time interval 150 s 200 s with the velocity:
L s
mol
s s
mol L mol L
t
A
^6
(^2) ( 200 150 )^6.^010
Rateofreaction(formationofO ) (^0 ,^0029 /^0 ,^0026 / )
while the velocity in the interval 350 s 400 s is:
L s
mol
s s
mol L mol L
t
A
^6
(^2) ( 400 350 )^4.^010
Rateofreaction(formationofO) (^0 ,^0035 /^0 ,^0033 / )
It is thereby worth noting that the rate of reaction is not a constant factor but actually decreases with time
in this case.
Reactions kinetics