Begin2.DVI

(Ben Green) #1
multiply row 1 by two and add the result to row 3, and (c) subtract row 1 from row

2. Performing these calculations produces

|A|=

∣∣
∣∣
∣∣
∣∣

1 0 0 2 6
0 1 0 1 3
0 0 1 1 3
0 −1 0 2 1
0 0 1 2 6

∣∣
∣∣
∣∣
∣∣

.

Now perform the operations: (a) add row 2 to row 4 and (b) subtract row 3 from

row 5. The determinant now has the form

|A|=

∣∣
∣∣
∣∣
∣∣

1 0 0 2 6
0 1 0 1 3
0 0 1 1 3
0 0 0 3 4
0 0 0 1 3

∣∣
∣∣
∣∣
∣∣

.

Observe that the row operations performed have produced zeros both above and

below the main diagonal. Next perform the operations of (a) subtracting twice row

5 from row 1, (b) subtracting row 5 from row 2, (c) subtracting row 5 from row 3,

and (d) subtracting row 5 from row 4. These operations produce

|A|=

∣∣
∣∣
∣∣
∣∣

1 0 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 2 1
0 0 0 1 3

∣∣
∣∣
∣∣
∣∣

.

By expanding |A|using cofactors of the first rows and associated subdeterminants,

there results

|A|= (1)(1)(1)

∣∣
∣∣2 1
1 3

∣∣
∣∣= 5.

A much more general procedure for calculating the determinant of a matrix A

is to use row operations and reduce |A|= det(A)to a triangular form having all zeros

below the main diagonal. For example, reduce Ato the form:

|A|= det(A) =

∣∣
∣∣
∣∣
∣∣
∣∣

a 11 a 12 a 13... a 1 n
0 a 22 a 23... a 2 n
0 0 a 33... a 3 n

..

.

..

.

..

.

... ..

.

0 0 0... a nn

∣∣
∣∣
∣∣
∣∣
∣∣

.
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