188 | Thermodynamics
(b) The work done could be determined by integration, but for this case
it is much easier to find it from the area under the process curve on a P-V
diagram, shown in Fig. 4–32:Therefore,The work is done by the system (to raise the piston and to push the atmo-
spheric air out of the way), and thus it is work output.
(c) Under the stated assumptions and observations, the energy balance on
the system between the initial and final states (process 1–3) can be
expressed asNet energy transfer Change in internal, kinetic,
by heat, work, and mass potential, etc., energiesThe mass of the system can be determined from the ideal-gas relation:The internal energies are determined from the air table (Table A–17) to beThus,Discussion The positive sign verifies that heat is transferred to the system.Qin767 kJQin140 kJ 1 0.697 kg 231 1113.52214.07 2 kJ>kg 4u 3 u @ 1400 K1113.52 kJ>kgu 1 u @ 300 K214.07 kJ>kgmP 1 V 1
RT 11 150 kPa 21 0.4 m^32
1 0.287 kPa#m^3 >kg#K 21 300 K 20.697 kgQinWb,out¢Um 1 u 3 u 12EinEout¬
¬
¢EsystemW 13 140 kJA 1 V 2 V 12 P 2 1 0.4 m^321 350 kPa 2 140 m^3 #kPa
3P, kPaV, m^32
350QAIRP 1 = 150 kPaV 1 = 400 L0.4T 1 = 27°C1501A0.8FIGURE 4 –32
Schematic and P-Vdiagram for
Example 4 –10.
Use actual data from the experiment
shown here to obtain the specific heat
of aluminum. See end-of-chapter
problem 4 –180.
© Ronald Mullisen
Use actual data from the experiment
shown here to obtain the specific heat
of aluminum. See end-of-chapter
problem 4 –179.
© Ronald Mullisen
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