Microsoft Word - Cengel and Boles TOC _2-03-05_.doc

(ff) #1
8–5 ■ EXERGY TRANSFER BY HEAT, WORK,
AND MASS

Exergy, like energy, can be transferred to or from a system in three forms:
heat, work,and mass flow.Exergy transfer is recognized at the system
boundary as exergy crosses it, and it represents the exergy gained or lost by
a system during a process. The only two forms of exergy interactions asso-
ciated with a fixed mass or closed system are heat transferand work.

Exergy by Heat Transfer, Q
Recall from Chap. 6 that the work potential of the energy transferred from
a heat source at temperature Tis the maximum work that can be obtained
from that energy in an environment at temperature T 0 and is equivalent to
the work produced by a Carnot heat engine operating between the source
and the environment. Therefore, the Carnot efficiency hc 1 T 0 /Trep-
resents the fraction of energy of a heat source at temperature Tthat can be
converted to work (Fig. 8–26). For example, only 70 percent of the energy
transferred from a heat source at T1000 K can be converted to work in
an environment at T 0 300 K.

440 | Thermodynamics


The properties of the refrigerant at the inlet and the exit states are

Inlet state:

Exit state:

The exergy change of the refrigerant during this compression process is
determined directly from Eq. 8–23 to be

Therefore, the exergy of the refrigerant increases during compression by
38.0 kJ/kg.
The exergy change of a system in a specified environment represents the
reversible work in that environment, which is the minimum work input
required for work-consuming devices such as compressors. Therefore, the
increase in exergy of the refrigerant is equal to the minimum work that
needs to be supplied to the compressor:

Discussion Note that if the compressed refrigerant at 0.8 MPa and 50°C
were to be expanded to 0.14 MPa and 10°C in a turbine in the same envi-
ronment in a reversible manner, 38.0 kJ/kg of work would be produced.

win,minc 2 c 1 38.0 kJ/kg

38.0 kJ/kg

 1 286.69246.36 2 kJ>kg 1 293 K 231 0.98020.9724 2 kJ>kg#K 4


 1 h 2 h 12 T 01 s 2 s 12

¢cc 2 c 1  1 h 2 h 12 T 01 s 2 s 12 

V^22 V^21
2

Q^0
g 1 z 2 z 12 Q

0

P 2 0.8 MPa
T 2 50°C


h 2 286.69 kJ>kg
s 2 0.9802 kJ>kg#K

P 1 0.14 MPa
T 1 10°C


h 1 246.36 kJ>kg
s 1 0.9724 kJ>kg#K

SEE TUTORIAL CH. 8, SEC. 5 ON THE DVD.

INTERACTIVE
TUTORIAL
Free download pdf