802 | Thermodynamics
Assumptions 1 The equilibrium composition consists of CO 2 , CO, and O 2.
2 The constituents of the mixture are ideal gases.
Analysis The stoichiometric and actual reactions in this case are as follows:
Stoichiometric:
Actual:
products reactants
(leftover)
C balance:
O balance:
Total number of moles:
Pressure:
The closest reaction listed in Table A–28 is CO 2 ∆CO ^1 – 2 O 2 , for which
ln KP2.801 at 2600 K. The reaction we have is the inverse of this, and
thus ln KP2.801, or KP16.461 in our case.
Assuming ideal-gas behavior for all components, the equilibrium constant
relation (Eq. 16–15) becomes
Substituting, we get
Solving for xyields
Then
Therefore, the equilibrium composition of the mixture at 2600 K and 304
kPa is
Discussion In solving this problem, we disregarded the dissociation of O 2
into O according to the reaction O 2 →2O, which is a real possibility at high
temperatures. This is because ln KP7.521 at 2600 K for this reaction,
which indicates that the amount of O 2 that dissociates into O is negligible.
(Besides, we have not learned how to deal with simultaneous reactions yet.
We will do so in the next section.)
1.906CO 2 0.094CO 2.074O 2
z 3
x
2
2.047
y 2 x0.094
x1.906
16.461
x
12 x 213 x> 221 >^2
a
3
5 x> 2
b
1 > 2
KP
NCOnCO 22
NCOnCONOnO 22
a
P
Ntotal
b
nCO 2 nCOnO 2
P304 kPa3.0 atm
Ntotalxyz 5
x
2
8 2 xy 2 z¬or z 3
x
2
2 xy ¬ or y 2 x
2CO3O 2 ¡xCO 2 yCOzO 2
CO^12 O 2 ∆CO 2 1 thus nCO 2 1, nCO1, and nO 2 ^122
(^1231552553)
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