BENDING MOMENT AND SHEAR FORCE DIAGRAMS 81
of the following simply supported beams;
hence, plot the bending moment and shearing
force diagrams.
- Figure 6.41(a)
[see Figure 6.44(a) on page 83)]
7 m
(a)
6 kN/m
AB
12 m
(b)
5 kN/m
AB
Figure 6.41 Simply supported beams
- Figure 6.41(b)
[see Figure 6.44(b) on page 83)]
Determine expressions for the bending mo-
ment and shearing force distributions for each
of the following cantilevers; hence, or other-
wise, plot the bending moment and shearing
force diagrams.
- Figure 6.42(a)
[see Figure 6.45(a) on page 83)]
5 m
(a)
6 kN/m
AB
9 m
(b)
5 kN/m
AB
Figure 6.42 Centilevers
- Figure 6.42(b)
[see Figure 6.45(b) on page 83)]
Exercise 33 Short answer questions on
bending moment and shear-
ing force diagrams
- Define a rigid-jointed framework
- Define bending moment
- Define sagging and hogging
- State two practical examples of uniformly
distributed loads - Show that the value of the maximum
shearing force for a beam simply sup-
ported at its ends, with a centrally placed
load of 3 kN, is 1.5 kN. - If the beam in question 5 were of span
4 m, show that its maximum bending
moment is 3 kN m. - Show that the values of maximum bend-
ing moment and shearing force for a can-
tilever of length 4 m, loaded at its free
end with a concentrated load of 3 kN, are
12 kN m and 3 kN.
Exercise 34 Multiple-choice questions on
bending moment and shear-
ing force diagrams (Answers
on page 284)
- A beam simply supported at its end, car-
ries a centrally placed load of 4 kN. Its
maximum shearing force is:
(a) 4 kN (b) 2 kN (c) 8 kN (d) 0 - Instead of the centrally placed load, the
beam of question 1 has a uniformly dis-
tributed load of 1 kN/m spread over its
span of length 4 m. Its maximum shearing
force is now:
(a) 4 kN (b) 1 kN
(c) 2 kN (d) 4 kN/n - A cantilever of length 3 m has a load
of 4 kN placed on its free end. The mag-
nitude of its maximum bending moment is:
(a) 3 kN m (b) 4 kN m
(c) 12 kN m (d) 4/3 kN/m
Exercise 34 continued on page 83