Highway Engineering

(Nandana) #1
X 0 is the degree of saturation on the opposing entry arm (ratio of flow to
capacity)
q 0 is the actual flow on the opposing arm, measured in vehicles per hour of green
time (excluding non-hooking right-turning vehicles)
lis the effective green time divided by the total cycle time, C
n 1 is the number of lanes within the opposing entry arm
s 0 is the saturation flow for each of the lanes on the opposing entry arm
Nsis the number of storage spaces within the junction which the right-turning
vehicles can use so as not to block the straight ahead stream.
(2) Sc
Scis the saturation flow occurring after the ‘effective green’ time within the lane
of opposed mixed turning traffic.

(During a traffic phase, the effective green time is the actual green time plus the
amber time but minus a deduction for starting delays.)
Sc=P(1 +Ns) (fX 0 )0.2¥3600/lC (5.32)

P= 1 +Si(ai -1)pi (5.33)
Pis the conversion factor from vehicles to passenger car units
aiis the pcu value of vehicle type i
piis the proportion of vehicles of type i.

The passenger car unit values used in connection with the design of a signalised
junction are given in Table 5.6.

136 Highway Engineering


Vehicle type pcu equivalent
Car/light vehicle 1.0
Medium commercial vehicle 1.5
Heavy commercial vehicle 2.3
Bus/coach 2.0

Table 5.6pcu values

Example 5.5 – Calculation of saturation flow for both opposed and
unopposed traffic lanes
The approach road shown in Fig. 5.30 is composed of two lanes, both
3.25 m wide. The nearside lane is for both left-turning and straight-ahead
traffic, with a ratio of 1 : 4 in favour of the straight through movement. The
non-nearside lane is for right-turning traffic. This movement is opposed. The
degree of saturation of the opposing traffic from the north is 0.6.

Contd
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