Geometry: An Interactive Journey to Mastery

(Greg DeLong) #1

  1. 6XSSRVHWKDWWKHJLYHQFLUFOHKDVUDGLXVr. Call its center F.
    'UDZDOLQHSDUDOOHOWRWKHJLYHQOLQHrXQLWVEHORZLW
    Call this line m.
    The diagram in Figure S.29.3 shows that the center of
    any circle tangent to the given circle and the given line
    is equidistant from F and m7KH\WKXVOLHRQDSDUDEROD
    with focus FDQGGLUHFWUL[m.


Lesson 30



  1. 6XSSRVHWKDWSRLQWVA and BDUHUHÀHFWHGDERXWDOLQHL to the
    points Ac and Bc, respectively. First assume that A and B lie on the
    same side of L.
    $OVROHWPEHWKHSRLQWRILQWHUVHFWLRQRIAAc and line L and Q
    EHWKHLQWHUVHFWLRQRIBBc and L ௘6HHFigure S.30.1௘ͽ
    Now, +BQP and +BQPc DUHFRQJUXHQWE\6$6ͼ௘BQ B Qc ,ERWK
    KDYHDULJKWDQJOHDQGERWKVKDUHPQ௘ͽ7KXVWKHWZRDQJOHVODEHOHGx
    DUHFRQJUXHQWͼ௘EHFDXVHWKH\DUHPDWFKLQJDQJOHVLQFRQJUXHQWWULDQJOHV௘ͽ
    and PB PBc,ͼ௘EHFDXVHWKH\DUHPDWFKLQJVLGHVLQFRQJUXHQWWULDQJOHV௘ͽ
    Thus, ‘#‘APB A PBcc,EHFDXVHWKH\ERWKKDYHPHDVXUHíx.
    6R+APB is congruent to +APBccE\6$6ͼ௘AP = AƍP, ‘#‘APB A PBcc, and PB = PBƍ௘ͽ
    Thus, AB = AƍBƍͼ௘EHFDXVHWKH\DUHPDWFKLQJVLGHVLQFRQJUXHQWWULDQJOHV௘ͽ
    6RWKHUHÀHFWLRQKDVLQGHHGSUHVHUYHGWKLVGLVWDQFHEHWZHHQA and B.
    In the same way, you can show that this distance is preserved in the case where A and B lie on opposite
    sides of the line, in the case where one of the points A or BOLHVRQWKHOLQHDQGLQWKHFDVHZKHUHWKH\ERWK
    GRͼ௘&KHFNWKLV௘ͽ
    7KXVDUHÀHFWLRQSUHVHUYHVWKHGLVWDQFHVEHWZHHQDOOSDLUVRISRLQWVLQWKHSODQHDQGWKHUHIRUH
    is an isometry.


rr

rr

F


m
Figure S.29.3

A
xx


B


Q


P L



Figure S.30.1
Free download pdf