Cliffs AP Chemistry, 3rd Edition

Figure 2

Analysis:

1. Determine the mass of chlorine in Compounds A and B.
   2.982 g A −1.770 g Pb = 1.212 g Cl in A
   2.364 g B −1.770 g Pb = 0.594 g Cl in B


2. Using the masses of lead and chlorine from the experiment, what relationship exists for
   Compounds A and B?
   A: 1.770 g Pb : 1.212 g Cl
   B: 1.770 g Pb : 0.594 g Cl


3. Using information from Question 2, calculate the number of grams of chlorine that would
   combine with 1 mole of lead in Compounds A and B.

A:..

..
gPb

gCl

mol Pb

gPb

1 770 141 9g Cl mol Pb

1 212

1

207 2 1

#:= -

B:.

..
gPb.

gCl

mol Pb

gPb

1 770 g Cl mol Pb

0 594

1

207 2

#:=69 5 -^1

Mh

Small flame

Hydrogen

source

Part III: AP Chemistry Laboratory Experiments