Order with respect to H 2 O 2 = First order according to Graph for Part 2
X = 1st order = 0.6107 *slope = order = x
[H 2 O 2 ] log [H 2 O 2 ] Time, sec Rate Log rate
0.04 −1.397940009 47 1.06383 × 10 –05 −4.973127854
0.03 −1.5228 78745 51 9.80392 × 10 –06 −5.008600172
0.022 −1.657577319 60 8.33333 × 10 –06 −5. 07 91812 4 6
0.018 −1.744727495 70 7.14286 × 10 –06 −5.146128036
0.014 −1.853871964 90 5.55556 × 10 –06 −5.255272505
Part III. Reaction Order with Respect to Hydronium Ion
Beaker A Beaker B
0.05 KI [I–] 0.05M Buffer 2 0.1 M [H 2 O 2 ] Time Initial Partial
(mL) (M) Na 2 S 2 O 3 (mL) H 2 O 2 (M) (s) rate Order
(mL) (mL) (M/s)
10.0 0.010 1.0 19.0 20.0 0.040 45 1 .11111 × 10 –5 0.037761
10.0 0.010 1.0 24.0 15.0 0.030 50 1.00000 × 10 –5 0.0172
10.0 0.010 1.0 28.0 11.0 0.022 75 6.66667 × 10 –6 −0.193819
10.0 0.010 1.0 30.0 9.0 0.018 104 4.80769 × 10 –6 −0.34387
10.0 0.010 1.0 32.0 7.0 0.014 130 3.84615 × 10 –6 −0.31940
Average order with respect to H 3 O+= 0.1604256 Zero order
Graph for Part 2
log [H 2 O 2 ]
log rate y = 0.6107x − 4.0937
log rate
linear (log rate)
-2 -1.5 -1 -0.5 0
-4.9
-5
-5.1
-5.2
-5.3
Laboratory Experiments