Answers and Explanations for the Practice Test
Section I (Multiple-Choice Questions)
- (C) Shielding and large ionic radius minimize electrostatic attraction.
- (A) F has only one negative oxidation state (−1).
- (D) Be2+now has electrons in the first energy level only.
- (C)
Oxygen is more electronegative than carbon, resulting in polar bonding. Because there are
no unshared pairs of electrons for carbon, a linear molecule results.
- (A)
There are three molecules listed that exhibit resonance:
- (E)
number of
bond order 2
bonding electrons antibonding electrons
number of
=
or bond order = (total valence electrons −non-bonding electrons) ×^1 ⁄ 2
= (11 −6) ×^1 ⁄ 2 = 2^1 ⁄ 2
Atomic Orbitals
for N
Atomic Orbitals
for O
2 p
2 p
2 s
2 s
Energy
O O O C O O C O O C O N O N O
S
O O
S
S
O O
S
O O
O C O
Answers and Explanations for the Practice Test
