The simplified solution (no losses; isothermal gas law) is given as
follows:Hmax1.4H 0 1.4(7510)119 m (absolute units). From equa-
tion (13.19),
Hmax H 0 Q 0 (LH 0 /gAV 0 )1/2
givingV 0 38 m^3 , and
HminH 0 Q 0 (LH 0 /gAV 0 )1/2
85 34 51 m.
ThereforeVmaxH 0 V 0 /Hmin(isothermal)63 m^3 , and the minimum volume
63 m^3.
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574 PUMPING STATIONS
