Filters and Equalizers 787The impedance may be represented as a single
complex number where the real part is the resistance
and the imaginary part is the reactance. The imaginary
part of a complex number is given by the magnitude
multiplied by the square root of negative one. The math-
ematical notation for this number is i but in engineering,
j is commonly used to avoid confusion in expressions
involving current.
(23-6)Analyzing a network in term of complex impedance
allows the calculation of both magnitude and phase at
any frequency according to(23-7)(23-8)
where,
T is the phase angle of the complex number,
A is the magnitude of the complex number.23.2.1.1 Capacitive NetworksThe capacitor has impedance that approaches a short
circuit at high frequency and an open circuit at low
frequency. The reactance of a capacitor is given by:(23-9)where;
Xc is the capacitive reactance,
f is the frequency in hertz,
C is the capacitance in farads.If a capacitor is connected in series with the signal
path as in Fig. 23-3A, the capacitor and the resistor
form a potential divider. Low frequencies will be atten-
uated as the impedance of the capacitor increases at
lower frequencies.(23-10)The cutoff frequency of this filter is at the frequency
where R=|ZC|, so substituting into Eq. 23-8, we find(23-11)Using the complex analysis in Eq. 23-8, we can deter-
mine the phase at this frequency.So according to Eqs. 23-7 and 23-8, the magnitude is
0.707 or 3 dB and the phase angle is 45 q.
If a capacitor is connected in parallel with the signal
path as in Fig. 23-3B, the capacitor and the resistor form
a potential divider. High frequencies will be attenuated
as the impedance of the capacitor reduces at higher
frequencies.(23-12)The cutoff frequency of this filter is at the frequency
where R=|ZC|, so substituting into Eq. 23-10, we find
that again(23-13)Using the complex analysis in Eq. 23-10, we can
determine the phase at this frequency.So according to Eqs. 23-7 and 23-8, the magnitude is
0.707 or 3 dB and the phase angle is +45q.Figure 23-3. Simple filter networks using only a capacitor
and a resistor.ZRjX+=T tan1– imaginary
real= ©¹§·------------------------Ainary= imag^2 +real^2XC^1
2 SfC-------------=A. High pass. B. Low pass.C
R CRVout Vin R
RZ+ c= --------------------f^1
2 SRC---------------=VoutVinuR
RjR+=-----------------1
1 +j-----------=1 – j
2=----------Vout VinZc
RZ+ C= ---------------------f^1
2 SRC---------------=VoutVinujR
RjR+=-------------------j
1 +j-----------=1 +j
2-----------=