CK-12 Geometry Concepts

(Elliott) #1

http://www.ck12.org Chapter 5. Relationships with Triangles


CK-12 Foundation: Chapter5MidsegmentTheoremB


Concept Problem Revisited


To the left is a picture of the 4thfigure in the fractal pattern. The number of triangles in each figure is 1, 4, 13, and



  1. The pattern is that each term increase by the next power of 3.


Vocabulary


A line segment that connects two midpoints of the sides of a triangle is called amidsegment. Amidpointis a point
that divides a segment into two equal pieces. Two lines areparallelif they never intersect. Parallel lines have slopes
that are equal. In a triangle, midsegments are always parallel to one side of the triangle.


Guided Practice


The vertices of 4 LMNareL( 4 , 5 ),M(− 2 ,− 7 )andN(− 8 , 3 ).



  1. Find the midpoints of all three sides, label themO,PandQ. Then, graph the triangle, it’s midpoints and draw in
    the midsegments.

  2. Find the slopes ofNMandQO.

  3. FindNMandQO.

  4. If the midpoints of the sides of a triangle areA( 1 , 5 ),B( 4 ,− 2 ), andC(− 5 , 1 ), find the vertices of the triangle.


Answers:



  1. Use the midpoint formula 3 times to find all the midpoints.


LandM=


( 4 +(− 2 )


2 ,


5 +(− 7 )
2

)


= ( 1 ,− 1 ), pointO

LandN=


( 4 +(− 8 )


2 ,


5 + 3
2

)


= (− 2 , 4 ), pointQ

MandN=


(− 2 +(− 8 )


2 ,


− 7 + 3
2

)


= (− 5 ,− 2 ), pointP

The graph would look like the graph below.



  1. The slope ofNMis−− 2 −^7 −(−^38 )=− 610 =−^53.


The slope ofQOis 1 −−^1 (−−^42 )=−^53.


From this we can conclude thatNM||QO. If we were to find the slopes of the other sides and midsegments, we
would findLM||QPandNL||PO.This is a property of all midsegments.



  1. Now, we need to find the lengths ofNMandQO. Use the distance formula.


NM=



(− 7 − 3 )^2 +(− 2 −(− 8 ))^2 =



(− 10 )^2 + 62 =



100 + 36 =



136 ≈ 11. 66


QO=



( 1 −(− 2 ))^2 +(− 1 − 4 )^2 =



32 +(− 5 )^2 =



9 + 25 =



34 ≈ 5. 83


Note thatQOishalfofNM.



  1. The easiest way to solve this problem is to graph the midpoints and then apply what we know from the Midpoint
    Theorem.

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