CK-12 Geometry Concepts

(Elliott) #1

http://www.ck12.org Chapter 9. Circles


BecauseAB⊥ADandDC⊥CB,ABandCBare tangent to the circle and also congruent. SetAB=CBand solve for
x.


4 x− 9 = 15
4 x= 24
x= 6

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CK-12 Foundation: Chapter9TangentLinesB


Vocabulary


Acircleis the set of all points that are the same distance away from a specific point, called thecenter. Aradius
is the distance from the center to the outer rim of a circle. Adiameteris a chord that passes through the center of
the circle. The length of a diameter is two times the length of a radius. Atangentis a line that intersects a circle in
exactly one point. Thepoint of tangencyis the point where the tangent line touches the circle.


Guided Practice



  1. Determine if the triangle below is a right triangle. Explain why or why not.

  2. Find the distance between the centers of the two circles. Reduce all radicals.

  3. IfDandAare the centers andAEis tangent to both circles, findDC.


Answers:



  1. To determine if the triangle is a right triangle, use the Pythagorean Theorem. 4



10 is the longest length, so we
will set it equal tocin the formula.


82 + 102?


(


4



10


) 2


64 + 1006 = 160


4 ABCis not a right triangle. And, from the converse of the Tangent to a Circle Theorem,CBis not tangent to



A.


  1. The distance between the two circles isAB. They are not tangent, however,AD⊥DCandDC⊥CB. Let’s addBE,
    such thatEDCBis a rectangle. Then, use the Pythagorean Theorem to findAB.


52 + 552 =AC^2


25 + 3025 =AC^2


3050 =AC^2


AC=



3050 = 5



122

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