CK-12 Geometry Concepts

http://www.ck12.org Chapter 11. Surface Area and Volume

Now, we can find the surface area.

SA= 2 π( 8 )^2 +( 16 π)( 21 )

= 128 π+ 336 π

= 464 π

Example C

Find the volume of the cylinder.

If the diameter is 16, then the radius is 8.

V=π 82 ( 21 ) = 1344 πunits^3

Watch this video for help with the Examples above.

MEDIA

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CK-12 Foundation: Chapter11CylindersB

Vocabulary

Acylinderis a solid with congruent circular bases that are in parallel planes. The space between the circles is
enclosed. A cylinder has aradiusand aheightand can also beoblique(slanted).

Surface areais a two-dimensional measurement that is the sum of the area of the faces of a solid. Volumeis a
three-dimensional measurement that is a measure of how much three-dimensional space a solid occupies.

Guided Practice

1. Find the volume of the cylinder.


2. If the volume of a cylinder is 484πin^3 and the height is 4 in, what is the radius?


3. Find the volume of the solid below.

Answers:

1.V=π 62 ( 15 ) = 540 πunits^3

2. Substitute what you know to the volume formula and solve forr.

484 π=πr^2 ( 4 )

121 =r^2

11 =r